04-layout-conflict/annotate_layout_conflict.py2205 字节
#!/usr/bin/env python3
"""第 21 章 §3.3 / §7.5:用 T.annotate_layout 制造一次布局冲突。
对照源码:
src/transform/layout_inference/layout_inference.cc:437-468 冲突三条出路
src/op/gemm.cc:254-266 reuse_existing_shared_layout
tilelang/language/annotations.py:45-62 annotate_layout 的契约
用法:
python3 annotate_layout_conflict.py --mode transpose
python3 annotate_layout_conflict.py --mode plain
"""
from __future__ import annotations
import argparse
import tilelang
import tilelang.language as T
def build(mode: str, block_M: int = 128, block_N: int = 128,
block_K: int = 32, dtype=T.float16, accum_dtype=T.float32):
@tilelang.jit
def matmul(A, B):
M, N, K = T.const("M, N, K")
A: T.Tensor((M, K), dtype)
B: T.Tensor((K, N), dtype)
C = T.empty((M, N), dtype)
with T.Kernel(T.ceildiv(N, block_N), T.ceildiv(M, block_M),
threads=128) as (bx, by):
A_shared = T.alloc_shared((block_M, block_K), dtype)
B_shared = T.alloc_shared((block_K, block_N), dtype)
C_local = T.alloc_fragment((block_M, block_N), accum_dtype)
if mode == "transpose":
# 与 swizzle 不兼容的纯转置布局:用来触发冲突路径。
bad = T.Layout([block_M, block_K],
lambda i, j: (j, i))
T.annotate_layout({A_shared: bad})
T.clear(C_local)
for k in T.Pipelined(T.ceildiv(K, block_K), num_stages=3):
T.copy(A[by * block_M, k * block_K], A_shared)
T.copy(B[k * block_K, bx * block_N], B_shared)
T.gemm(A_shared, B_shared, C_local)
T.copy(C_local, C[by * block_M, bx * block_N])
return C
return matmul
def main() -> int:
parser = argparse.ArgumentParser()
parser.add_argument("--mode", choices=["plain", "transpose"],
default="transpose")
args = parser.parse_args()
matmul = build(args.mode)
print(f"[info] 已构造 mode={args.mode} 的 kernel 包装。")
print("[info] 本机没有 GPU;要观察冲突,请在有卡机器上做一次带数据的调用。")
return 0
if __name__ == "__main__":
raise SystemExit(main())